-6x^2+25x-25=0

Solution for -6x^2+25x-25=0 equation:

-6x^2+25x-25=0

a = -6; b = 25; c = -25;
Δ = b2-4ac
Δ = 252-4·(-6)·(-25)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*-6}=\frac{-30}{-12}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*-6}=\frac{-20}{-12}
=1+2/3
$